scalation.math

LongWithExp

Related Docs: object LongWithExp | package math

case class LongWithExp(m: Long) extends Product with Serializable

The LongWithExp class defines an expontiation operator '~^' for Longs. To maintain 64 bit precision, no floating point operations are used.

m

the long base

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Instance Constructors

  1. new LongWithExp(m: Long)

    m

    the long base

Value Members

  1. final def !=(arg0: Any): Boolean

    Definition Classes
    AnyRef → Any
  2. final def ##(): Int

    Definition Classes
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  3. final def ==(arg0: Any): Boolean

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  4. final def asInstanceOf[T0]: T0

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  5. def clone(): AnyRef

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    protected[java.lang]
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    @throws( ... )
  6. final def eq(arg0: AnyRef): Boolean

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  7. def finalize(): Unit

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    @throws( classOf[java.lang.Throwable] )
  8. final def getClass(): Class[_]

    Definition Classes
    AnyRef → Any
  9. final def isInstanceOf[T0]: Boolean

    Definition Classes
    Any
  10. val m: Long

    the long base

  11. final def ne(arg0: AnyRef): Boolean

    Definition Classes
    AnyRef
  12. final def notify(): Unit

    Definition Classes
    AnyRef
  13. final def notifyAll(): Unit

    Definition Classes
    AnyRef
  14. def pow(n: Long): Long

  15. def root(n: Long): Long

    Find the n-th root of m, i.e., m ~^ (1/n) for scala Longs.

    Find the n-th root of m, i.e., m ~^ (1/n) for scala Longs.

    n

    the root level

    See also

    http://en.wikipedia.org/wiki/Shifting_nth_root_algorithm

  16. final def synchronized[T0](arg0: ⇒ T0): T0

    Definition Classes
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  17. final def wait(): Unit

    Definition Classes
    AnyRef
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    @throws( ... )
  18. final def wait(arg0: Long, arg1: Int): Unit

    Definition Classes
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    @throws( ... )
  19. final def wait(arg0: Long): Unit

    Definition Classes
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    @throws( ... )
  20. def ~^(n: Long): Long

    Exponentiation operator for scala Longs (m ~^ n). Compute: "math.pow (m, n).toLong" without using floating point, so as to not lose precision.

    Exponentiation operator for scala Longs (m ~^ n). Compute: "math.pow (m, n).toLong" without using floating point, so as to not lose precision.

    n

    the long exponent

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