c

scalation.minima

IntegerLocalSearch

class IntegerLocalSearch extends AnyRef

The IntegerLocalSearch class performs local search to find minima of functions defined on integer vector domains (z^n).

minimize f(x) subject to g(x) <= 0, x in Z^n

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Instance Constructors

  1. new IntegerLocalSearch(f: (VectorI) ⇒ Double, g: (VectorI) ⇒ Double = null, maxStep: Int = 5)

    f

    the objective function to be minimize ('f' maps an integer vector to a double)

    g

    the constraint function to be satisfied, if any

    maxStep

    the maximum/starting step size (make larger for larger domains)

Type Members

  1. type Vec_Func = (VectorI, Double)

    Pair consisting of an integer vector and its functional value (a double)

Value Members

  1. final def !=(arg0: Any): Boolean
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  2. final def ##(): Int
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  3. final def ==(arg0: Any): Boolean
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  5. def clone(): AnyRef
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  6. final def eq(arg0: AnyRef): Boolean
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  7. def equals(arg0: Any): Boolean
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  8. def fg(x: VectorI): Double

    The objective function 'f' re-scaled by a weighted penalty, if constrained.

    The objective function 'f' re-scaled by a weighted penalty, if constrained.

    x

    the coordinate values of the current point

  9. final def getClass(): Class[_]
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  10. def hashCode(): Int
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  11. final def isInstanceOf[T0]: Boolean
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  12. def minNeighbor(x_f0: Vec_Func, i: Int, step: Int = 1): Vec_Func

    Find a minimal neighbor of the current point 'x' that is a distance step away.

    Find a minimal neighbor of the current point 'x' that is a distance step away. Let 'x' be the current point with 'y' being a step down and 'x' being a step up in dimension 'i'. Recurse to handle all of the dimensions.

    x_f0

    the current pair (the point and its functional value)

    i

    the 'i'th dimension or coordinate (facilitates recursion)

    step

    examine points that are this far away

  13. final def ne(arg0: AnyRef): Boolean
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  14. final def notify(): Unit
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  15. final def notifyAll(): Unit
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  16. def solve(x: VectorI): Vec_Func

    Solve the minimization problem by repeatedly moving to a minimal neighbor until there is no improvement.

    Solve the minimization problem by repeatedly moving to a minimal neighbor until there is no improvement.

    x

    the starting point for the search

  17. final def synchronized[T0](arg0: ⇒ T0): T0
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  18. def toString(): String
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  19. final def wait(arg0: Long, arg1: Int): Unit
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  20. final def wait(arg0: Long): Unit
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  21. final def wait(): Unit
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  1. def finalize(): Unit
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